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In a rural area of the Philippines, an old Jeepney is used to transport passengers along a bumpy dirt road route. The Jeepney is 11 meters long, with 10 meters of that length used for passenger seating in two rows facing each other. The vehicle weighs 3200 kg when empty.
Consider the following information:
a) Based on the seating space available, what is the maximum number of passengers that could fit in the jeepney?
b) Based on the weight limits of the tires, what is the maximum number of passengers the jeepney could carry?
c) Given both the seating space and weight constraints, how many passengers should the driver allow on the jeepney for a safe journey?
d) If the jeepney makes 4 trips a day on this route, how many passengers can it transport in a week?
a) Seating space calculation:
– Total seating length: 10 meters = 1000 cm
– Space per passenger: 50 cm + 10 cm (safety space) = 60 cm
– Number of passengers per row: 1000 cm ÷ 60 cm = 16.67
– Rounded down: 16 passengers per row
– Total for two rows: 16 × 2 = 32 passengers
b) Weight limit calculation:
– Total additional weight capacity: 500 kg × 4 tires = 2000 kg
– Weight capacity per passenger: 60 kg
– Maximum passengers by weight: 2000 kg ÷ 60 kg = 33.33
– Rounded down: 33 passengers
c) Safe passenger limit:
The lower of the two constraints should be used for safety.
Seating constraint: 32 passengers
Weight constraint: 33 passengers
Safe passenger limit: 32 passengers
d) Weekly passenger capacity:
– Daily capacity: 32 passengers × 4 trips = 128 passengers
– Weekly capacity (assuming 7-day operation): 128 × 7 = 896 passengers
Therefore, the jeepney can safely transport 32 passengers per trip, and up to 896 passengers in a week.
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